function F = KBt1F(x)
%

F(1) = -0.51519 + (1-x(2));
F(2) = -0.84802 + (1-x(2)) + x(1) + x(5) - x(6)*x(5) - x(7)*x(1) - x(7)*x(5) + x(7)*x(6)*x(5);
F(3) = -0.87803 + (1-x(2)) + (1-x(1)) + x(3) - x(8)*x(3) - x(9)*(1-x(1)) - x(9)*x(3) + x(9)*x(8)*x(3);
F(4) = -0.45222 + (1-x(5));
F(5) = -0.7134 + (1-x(5)) + (1-x(3)) - x(10)*(1-x(3));
F(6) = -0.91823 + (1-x(3)) + (1-x(1)) + x(5) - x(11)*x(5) - x(12)*(1-x(1)) - x(12)*x(5) + x(12)*x(11)*x(5);
F(7) = -0.78178 + (1-x(3)) + (1-x(2)) - x(13)*(1-x(2));
F(8) = -0.77042 + (1-x(4)) + (1-x(1)) - x(14)*(1-x(1));
F(9) = -0.83937 + (1-x(1)) + x(3) + x(5) - x(15)*x(5) - x(16)*x(3) - x(16)*x(5) + x(16)*x(15)*x(5);
F(10) = -0.8933 + (1-x(2)) + x(3) + x(5) - x(17)*x(5) - x(18)*x(3) - x(18)*x(5) + x(18)*x(17)*x(5);
