function F = KB48F(x)
%

F(1) = -0.99998+(1-x(4))+(1-x(3))+(1-x(1))+x(2)+x(5)-(1-x(4))*(1-x(3))-(1-x(4))*(1-x(1))-(1-x(4))*x(2)-(1-x(4))*x(5)-(1-x(3))*(1-x(1))-(1-x(3))*x(2)-(1-x(3))*x(5)-(1-x(1))*x(2)-(1-x(1))*x(5)-x(2)*x(5)+(1-x(4))*(1-x(3))*(1-x(1))+(1-x(4))*(1-x(3))*x(2)+(1-x(4))*(1-x(3))*x(5)+(1-x(4))*(1-x(1))*x(2)+(1-x(4))*(1-x(1))*x(5)+(1-x(4))*x(2)*x(5)+(1-x(3))*(1-x(1))*x(2)+(1-x(3))*(1-x(1))*x(5)+(1-x(3))*x(2)*x(5)+(1-x(1))*x(2)*x(5)-(1-x(4))*(1-x(3))*(1-x(1))*x(2)-(1-x(4))*(1-x(3))*(1-x(1))*x(5)-(1-x(4))*(1-x(3))*x(2)*x(5)-(1-x(4))*(1-x(1))*x(2)*x(5)-(1-x(3))*(1-x(1))*x(2)*x(5)+(1-x(4))*(1-x(3))*(1-x(1))*x(2)*x(5);
